Search vs. Action and searching for strings : awk

mglenney · #1 06-02-2009, 07:58 PM

I have awk embedded in a shell script and I am trying to search for a string of text after a certain point in the file and I need to return number of lines with that string and number of lines in the input file.

I have the following:

Code:

set -- $(awk -v lines=$lineslastrun -v pattern="$searchpattern" '
  BEGIN { count=0 }
  NR > lines
  /pattern/ { count++ }
  END { print NR; print count }
' $logfile)
echo $1
echo $2

In the script, those variables are currently set as:
$lineslastrun = 8
$searchpattern = "test data"

The file being searched:

Code:

[a.mjglenne@plaxafm1001 ~]$ cat testlog
one
two
three
test data
five
six
seven
eight
nine
ten
eleven
twelve
thirteen
fourteen
fifteen
test data
seventeen
eighteen
test data
testdata

So I want to check each line of the file, starting at line 9 and each time I find a line with "test data" somewhere in it I want to increase the counter by 1. At the end I want to output the total number of lines in the input file and the count.

If I run the bash script with 'set -x' I see the following output

Code:

++ awk -v lines=8 -v 'pattern=test data' '
  BEGIN { count=0 }
  NR > lines
  /pattern/ { count++ }
  END { print NR; print count }
' ./testlog
+ set -- nine ten eleven twelve thirteen fourteen fifteen test data seventeen eighteen test data testdata 20 0
+ echo nine
nine
+ echo ten
ten

Looks like awk is returning lines that don't match AND it's not able to search for my pattern. It is returning the number of lines (20) and the count (0) but it seems to be returning everything. The "echo nine" and "echo ten" you see there are 'echo $1' and 'echo $2' in the bash script. This would work great if I could get awk to only output NR and count.

Appreciate any help. Thanks

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Search vs. Action and searching for strings : awk

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