PLEASE HELP WITH STRUCTURES! - basic.visual
This is a discussion on PLEASE HELP WITH STRUCTURES! - basic.visual ; I am in the middle of creating a program, I have a structure like
this:
structure names
dim first_name as string
dim last_name as string
dim address as string
end structure
inside the module
I have
dim astructure() as names
...
-
PLEASE HELP WITH STRUCTURES!
I am in the middle of creating a program, I have a structure like
this:
structure names
dim first_name as string
dim last_name as string
dim address as string
end structure
inside the module
I have
dim astructure() as names
if I build a sort routine that tests the element of the array of
structures such as:
if astructure.first_name (i)> astructure. first_name then
do switch
do switch routine
temp=astructure.first_name(i)
astructure.first_name(i)=structure.first_name(i+1)
astructure.first_name=temp
what happens to the rest of the element of the array of structures do
they go with the first one?
In other words, does the whole structure get switch as a whole unit?
John
-
Re: PLEASE HELP WITH STRUCTURES!
Is this a VB.NET question? If so, consider the following...
Almost everybody in this newsgroup is using VB6 or lower. While you may get
a stray answer to VB.NET questions here, you should ask them in newsgroups
devoted exclusively to .NET programming. Look for newsgroups with either the
word "dotnet" or "vsnet" in their name.
For the microsoft news server, try these newsgroups...
microsoft.public.dotnet.general
microsoft.public.dotnet.languages.vb
microsoft.public.vsnet.general
There are some others, but these should get you started.
Rick - MVP
"RBCC" <putgarbagehere@email.com> wrote in message
news:Xns9474C9421AF4Bnewsgroupsveinet@216.196.97.132...
> I am in the middle of creating a program, I have a structure like
> this:
>
> structure names
> dim first_name as string
> dim last_name as string
> dim address as string
> end structure
>
> inside the module
> I have
> dim astructure() as names
>
> if I build a sort routine that tests the element of the array of
> structures such as:
>
> if astructure.first_name (i)> astructure. first_name then
> do switch
>
>
> do switch routine
> temp=astructure.first_name(i)
> astructure.first_name(i)=structure.first_name(i+1)
> astructure.first_name=temp
>
> what happens to the rest of the element of the array of structures do
> they go with the first one?
>
> In other words, does the whole structure get switch as a whole unit?
>
> John
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