empirical mode decomposition..please help - DSP

This is a discussion on empirical mode decomposition..please help - DSP ; hi everyone, million thanks in advance...i would like to know about EMD which is part one of hilbert huang transform. the procedure of EMD is : 1)For a signal X(t), let m1 be the mean of its upper and lower ...

+ Reply to Thread
Results 1 to 8 of 8

empirical mode decomposition..please help

  1. Default empirical mode decomposition..please help

    hi everyone, million thanks in advance...i would like to know about EMD
    which is part one of hilbert huang transform. the procedure of EMD is :

    1)For a signal X(t), let m1 be the mean of its upper and lower envelopes
    as determined from a cubic-spline interpolation of local maxima and minima.
    The locality is determined by an arbitrary parameter; the calculation time
    and the effectiveness of the EMD depends greatly on such a parameter.
    2)The first component h1 is computed:
    h1=X(t)-m1
    3)In the second sifting process, h1 is treated as the data, and m11 is the
    mean of h1’s upper and lower envelopes:
    h11=h1-m11
    This sifting procedure is repeated k times, until h1k is an IMF, that is:
    h1(k-1)-m1k=h1k
    Then it is designated as c1=h1k, the first IMF component from the data,
    which contains the shortest period component of the signal. We separate it
    from the rest of the data: X(t)-c1 = r1 The procedure is repeated on rj:
    r1-c2 = r2,....,rn-1 - cn = rn.

    the problem is, which iteration result should i apply the hilbert
    transform(2nd part of HHT)?
    please help me, i`m stuck. thanks again




  2. Default Re: empirical mode decomposition..please help

    On 10 Nov, 15:00, "amidala" <raseedaham...@yahoo.com> wrote:
    > hi everyone, million thanks in advance...i would like to know about EMD
    > which is part one of hilbert huang transform.


    I did look briefly into the Hilbert-Huang transform a few
    years ago. My interest faded when I learned that it was
    patented. One might breach patent laws by discussing it.

    > the procedure of EMD is :
    >
    > 1)For a signal X(t), let m1 be the mean of its upper and lower envelopes
    > as determined from a cubic-spline interpolation of local maxima and minima.
    > The locality is determined by an arbitrary parameter; the calculation time
    > and the effectiveness of the EMD depends greatly on such a parameter.


    Which accounts for the word "Empirical" in "Empirical
    Mode Decomposition".

    > 2)The first component h1 is computed:
    >   h1=X(t)-m1
    > 3)In the second sifting process, h1 is treated as the data, and m11 is the
    > mean of h1’s upper and lower envelopes:
    > h11=h1-m11
    > This sifting procedure is repeated k times, until h1k is an IMF, that is:
    > h1(k-1)-m1k=h1k
    > Then it is designated as c1=h1k, the first IMF component from the data,
    > which contains the shortest period component of the signal. We separate it
    > from the rest of the data: X(t)-c1 = r1 The procedure is repeated on rj:
    > r1-c2 = r2,....,rn-1 - cn = rn.
    >
    > the problem is, which iteration result should i apply the hilbert
    > transform(2nd part of HHT)?
    > please help me, i`m stuck. thanks again


    That's the second reason the term "Empirical" is used
    for the algorithm: You as ****yst is responsible for
    choosing the parameter(s) that best fits the data.
    Or your purpose. Or some other arbitrarily chosen parameter.

    The word "empirical" doesn't sound wuite as bad as
    "subjective" or "guesswork" (and maybe it isn't), but
    that's the kind of context where it belongs.

    Rune

  3. Default Re: empirical mode decomposition..please help

    Rune Allnor wrote:
    > On 10 Nov, 15:00, "amidala" <raseedaham...@yahoo.com> wrote:
    >> hi everyone, million thanks in advance...i would like to know about EMD
    >> which is part one of hilbert huang transform.

    >
    > I did look briefly into the Hilbert-Huang transform a few
    > years ago. My interest faded when I learned that it was
    > patented. One might breach patent laws by discussing it.


    AFAIK there's no restriction anywhere on _discussing_ a patented
    technology -- there certainly isn't one in the US. The whole point of a
    patent is to induce the inventor (or thief, depending on who you're
    talking to) of a technology to put it into the public domain, in return
    for which the inventor (I'll stop being provocative) gets a monopoly on
    the technology for some period.

    That way (in theory) the invention gets put into the public domain so
    that after the patent has lapsed (and the inventor has presumably made
    his bundle of money) anyone can go and make the stuff.

    Even though patent law in most places seems to have morphed into
    protectionism for big corporations and a stifling, rather than an
    encouragement, to innovation, I would be surprised that it could be used
    as a means of abrogating one's freedom of speech.

    (Non-disclosure agreements are different -- in that case you're signing
    a contract where you promise not to blab in return for "hush money" in
    cash or barter.)

    Now, go and try to _sell_ me a product using patented technology; then
    some feathers may fly. See
    http://groups.google.com/group/sci.e...16b2336f4e4ce;
    pay particular attention to option "H".

    Note that even if you _do_ sell me patented technology, no government
    agency (in the US at least) is going to go after you. It's the
    responsibility of the patent owner to go after you (and possibly me) to
    make you (and possibly me) pay for his intellectual property, and it
    must be done through civil courts.

    I suspect the law is pretty much the same in any "Western" country.

    >> the procedure of EMD is :
    >>
    >> 1)For a signal X(t), let m1 be the mean of its upper and lower envelopes
    >> as determined from a cubic-spline interpolation of local maxima and minima.
    >> The locality is determined by an arbitrary parameter; the calculation time
    >> and the effectiveness of the EMD depends greatly on such a parameter.

    >
    > Which accounts for the word "Empirical" in "Empirical
    > Mode Decomposition".
    >
    >> 2)The first component h1 is computed:
    >> h1=X(t)-m1
    >> 3)In the second sifting process, h1 is treated as the data, and m11 is the
    >> mean of h1’s upper and lower envelopes:
    >> h11=h1-m11
    >> This sifting procedure is repeated k times, until h1k is an IMF, that is:
    >> h1(k-1)-m1k=h1k
    >> Then it is designated as c1=h1k, the first IMF component from the data,
    >> which contains the shortest period component of the signal. We separate it
    >> from the rest of the data: X(t)-c1 = r1 The procedure is repeated on rj:
    >> r1-c2 = r2,....,rn-1 - cn = rn.
    >>
    >> the problem is, which iteration result should i apply the hilbert
    >> transform(2nd part of HHT)?
    >> please help me, i`m stuck. thanks again

    >
    > That's the second reason the term "Empirical" is used
    > for the algorithm: You as ****yst is responsible for
    > choosing the parameter(s) that best fits the data.
    > Or your purpose. Or some other arbitrarily chosen parameter.
    >
    > The word "empirical" doesn't sound wuite as bad as
    > "subjective" or "guesswork" (and maybe it isn't), but
    > that's the kind of context where it belongs.
    >
    > Rune


    I like "wild-ass guess". Unless I'm talking to a client; then I say
    "empirical" or "heuristic".

    --

    Tim Wescott
    Wescott Design Services
    http://www.wescottdesign.com

    Do you need to implement control loops in software?
    "Applied Control Theory for Embedded Systems" gives you just what it says.
    See details at http://www.wescottdesign.com/actfes/actfes.html

  4. Default Re: empirical mode decomposition..please help



    Tim Wescott wrote:

    > Rune Allnor wrote:
    >


    >> The word "empirical" doesn't sound wuite as bad as
    >> "subjective" or "guesswork" (and maybe it isn't), but
    >> that's the kind of context where it belongs.


    > I like "wild-ass guess". Unless I'm talking to a client; then I say
    > "empirical" or "heuristic".


    "Heuristic" sounds like "hebrew", so it is like something that you could
    expect from a jew...

    VLV




  5. Default Re: empirical mode decomposition..please help

    Thank You for your reply. I really appreciate it.

    I would like to know further regarding patented Hilbet Huang Transform as
    u have mentioned before.

    "Rune:
    I did look briefly into the Hilbert-Huang transform a few
    years ago. My interest faded when I learned that it was
    patented. One might breach patent laws by discussing it."

    May I know, do you mean that I cannot use Hilbert Huang Transform in my
    study? Or is it mean that I cannot discuss it openly once it has been
    patented (i.e forum, conference,etc)? I try to search about the issue, but
    I can't found any.

    Currently, I have found some latest publication (2008) about signal
    processing that used Hilbert Huang Transform.

    I`m looking forward to hear from you and Thank You in advanced for your
    coorperation.

    Thanks and Regards.


  6. Default Re: empirical mode decomposition..please help

    amidala wrote:
    > Thank You for your reply. I really appreciate it.
    >
    > I would like to know further regarding patented Hilbet Huang Transform as
    > u have mentioned before.
    >
    > "Rune:
    > I did look briefly into the Hilbert-Huang transform a few
    > years ago. My interest faded when I learned that it was
    > patented. One might breach patent laws by discussing it."
    >
    > May I know, do you mean that I cannot use Hilbert Huang Transform in my
    > study? Or is it mean that I cannot discuss it openly once it has been
    > patented (i.e forum, conference,etc)? I try to search about the issue, but
    > I can't found any.
    >
    > Currently, I have found some latest publication (2008) about signal
    > processing that used Hilbert Huang Transform.
    >
    > I`m looking forward to hear from you and Thank You in advanced for your
    > coorperation.


    I don't know the law where you are, but I never heard of patents
    anywhere that prevented discussion or, in practice, experimentation.
    What a US patent gives the owner is the right to sue foe any damages to
    his income that an infringer causes. US patents are available for a
    nominal fee (that used to be $0.25) to anyone who asks, and is invalid
    if the disclosure doesn't provide enough information so that "a
    practitioner versed in the art" can reproduce the invention. Rest easy!

    Jerry
    --
    Engineering is the art of making what you want from things you can get.
    ŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻŻ

  7. Default Re: empirical mode decomposition..please help

    On 11 Nov, 02:38, "amidala" <raseedaham...@yahoo.com> wrote:
    > Thank You for your reply. I really appreciate it.
    >
    > I would like to know further regarding patented Hilbet Huang Transform as
    > u have mentioned before.
    >
    > "Rune:
    > I did look briefly into the Hilbert-Huang transform a few
    > years ago. My interest faded when I learned that it was
    > patented. One might breach patent laws by discussing it."
    >
    > May I know, do you mean that I cannot use Hilbert Huang Transform in my
    > study? Or is it mean that I cannot discuss it openly once it has been
    > patented (i.e forum, conference,etc)? I try to search about the issue, but
    > I can't found any.


    I don't know what restrictions apply regarding patents.
    Which is why the simple solution, in order to avoid
    potentially serious trouble, is to not discuss them.

    I've heard of companies who grant employees who invent
    stuff that they (the company) patent the right to use
    the invention "for personal use." Some of the comments
    in this thread indicate that everyone have this right
    anyway. But again, I'm not a lawyer so I don't know the
    details.

    So *maybe* it's OK if you play with patented technology
    on your experiments, and *maybe* it's OK to mention what
    you did on, say, a conference.

    Now, what happens if somebody, based on such a presentation,
    asks for your collaboration or help in some project? At this
    point it's no longer a matter of "personal use" or
    "experimentation", so with a little bit of bad luck, all
    hell might break loose.

    Even if everything else is harmless, merely letting people
    know that you look into patented technology might cause
    suspicions among patent holders along the lines of "Do
    these people use my patent? They don't pay for it..."
    Which will make no one any good.

    So the only advice I can give is:

    1) Find out if the techniques you use are patented.
    2) Find out what restrictions wrt patents apply in
    your location and line of work.
    3) Decide whether you are better served by leaving
    patented technology alone.
    4) Whatever you decide to do, keep quiet about it.

    Rune

  8. Default Re: empirical mode decomposition..please help

    On Nov 10, 12:27 pm, Vladimir Vassilevsky <antispam_bo...@hotmail.com>
    wrote:
    > Tim Wescott wrote:
    > > Rune Allnor wrote:

    >
    > >> The word "empirical" doesn't sound wuite as bad as
    > >> "subjective" or "guesswork" (and maybe it isn't), but
    > >> that's the kind of context where it belongs.

    > > I like "wild-ass guess".  Unless I'm talking to a client; then I say
    > > "empirical" or "heuristic".

    >
    > "Heuristic" sounds like "hebrew", so it is like something that you could
    > expect from a jew...
    >
    > VLV


    wow, I used to think you were a smart guy...

    guess I ws wrong.

    Mark

+ Reply to Thread