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#1
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| Is it possible to create an ARRAY [LINKED_LIST [G]] more elegantly in a single step? If the number of array-elements is not known in advance, is there a dynamic version? bucket_sort is -- Sort array. local buckets: ARRAY [LINKED_LIST [G]] bucket_0: LINKED_LIST [G] bucket_1: LINKED_LIST [G] bucket_2: LINKED_LIST [G] bucket_3: LINKED_LIST [G] bucket_4: LINKED_LIST [G] do create buckets.make (0, 4) create bucket_0.make create bucket_1.make create bucket_2.make create bucket_3.make create bucket_4.make buckets.item (0) := bucket_0 buckets.item (1) := bucket_1 buckets.item (2) := bucket_2 buckets.item (3) := bucket_3 buckets.item (4) := bucket_4 end Many thanks Roman |
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#2
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| Sorry, I have not been coding in the wonderful eiffel language since some time, so it might be impossible to compile what I write, but I think a loop will do the job: bucket_sort is -- Sort array. local buckets: ARRAY [LINKED_LIST [G]] bucket: LINKED_LIST [G] i,last: INTEGER do last:=4 -- last could also be set by another -- method and not be local create buckets.make (0,last) from i:=0 until i>last loop create bucket.make buckets.item(i) := bucket end --loop end --bucket_sort Roman Töngi a écrit : > Is it possible to create an ARRAY [LINKED_LIST [G]] more elegantly in a > single step? If the number of array-elements is not known in advance, is > there a dynamic version? > > bucket_sort is > -- Sort array. > local > buckets: ARRAY [LINKED_LIST [G]] > bucket_0: LINKED_LIST [G] > bucket_1: LINKED_LIST [G] > bucket_2: LINKED_LIST [G] > bucket_3: LINKED_LIST [G] > bucket_4: LINKED_LIST [G] > do > create buckets.make (0, 4) > create bucket_0.make > create bucket_1.make > create bucket_2.make > create bucket_3.make > create bucket_4.make > buckets.item (0) := bucket_0 > buckets.item (1) := bucket_1 > buckets.item (2) := bucket_2 > buckets.item (3) := bucket_3 > buckets.item (4) := bucket_4 > end > > > Many thanks > Roman |
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#3
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| Works fine. Thx |
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