Day of Year... Too lazy for a two-line solution...

#1 08-22-2008, 02:49 PM

Hi IDL Wizards,

I handle all date manipulation in my routines using JULDAY(), CALDAT,
and the C() format code. Going from Day-of-Year to Julian Date is
easy:

Julian_Date = JULDAY(1,Day_Of_Year,Year,0,0,0)

Getting Day-of-Year back out requires this, *unless you can do
better*:

CALDAT,Julian_Date,Null,Null,Year
Day_Of_Year = Julian_Date - JULDAY(12,31,Year-1,0,0,0)

I would really like a one-line solution with no stray variables.
Anyone have one?

--Edward H.

#2 08-22-2008, 03:43 PM

Ed Hyer writes:

> I handle all date manipulation in my routines using JULDAY(), CALDAT,
> and the C() format code. Going from Day-of-Year to Julian Date is
> easy:
>
> Julian_Date = JULDAY(1,Day_Of_Year,Year,0,0,0)
>
> Getting Day-of-Year back out requires this, *unless you can do
> better*:
>
> CALDAT,Julian_Date,Null,Null,Year
> Day_Of_Year = Julian_Date - JULDAY(12,31,Year-1,0,0,0)
>
> I would really like a one-line solution with no stray variables.
> Anyone have one?

Would a call to a three-line function qualify as an answer?

Cheers,

David

--
David Fanning, Ph.D.
Fanning Software Consulting, Inc.
Coyote's Guide to IDL Programming: http://www.dfanning.com/
Sepore ma de ni thui. ("Perhaps thou speakest truth.")

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