| Register | FAQ | Calendar | Search | Today's Posts | Mark Forums Read |
|
#481
| |||
| |||
| "Bob Myers" <nospamplease@address.invalid> wrote: >"isw" <isw@witzend.com> wrote in message >news:isw-00A66F.10310528082007@newsgroups.comcast.net... >> In article <87mywcjdq7.fld@apaflo.com>, >> floyd@apaflo.com (Floyd L. Davidson) wrote: >> >>> Most physical channels are inherently analog! Wire >>> cables and fiber optic cables are two examples. Digital >>> signals are commonly sent via either of them. >> >> I'll probably regret jumping in here, but: >> >> The *message* may be digital, but the *signals* are most definitely >> analog. > >The SIGNALS are electrical or optical. Really? Nothing could be acoustical? Are you deaf? Regardless, that does not address the incorrectness of stating that all signals are analog. Morse code is not analog. -- Floyd L. Davidson <http://www.apaflo.com/floyd_davidson> Ukpeagvik (Barrow, Alaska) floyd@apaflo.com |
|
#482
| |||
| |||
| "Floyd L. Davidson" <floyd@apaflo.com> wrote in message news:87r6lojir0.fld@apaflo.com... > >> Yes, you do have an infinite number of *voltages* > >> between 3 and 18, > > > >Only in theory, in practice nothing is infinite in this universe. > >Noise will set the resolution limit. > > The noise itself has an infinite number of possible > values, OK, prove it. > and therefore even if the signal itself is > supposed to be just 1 value, add the noise and there are > an infinite number of values. Only for those who failed mathematics at high school. MrT. |
|
#483
| |||
| |||
| In article <87wsvfi4rc.fld@apaflo.com>, floyd@apaflo.com (Floyd L. Davidson) wrote: > isw <isw@witzend.com> wrote: > >In article <87mywcjdq7.fld@apaflo.com>, > > floyd@apaflo.com (Floyd L. Davidson) wrote: > > > >> Most physical channels are inherently analog! Wire > >> cables and fiber optic cables are two examples. Digital > >> signals are commonly sent via either of them. > > > >I'll probably regret jumping in here, but: > > > >The *message* may be digital, but the *signals* are most definitely > >analog. > > That is not correct. Whether a message is or not > digital is entirely unrelated to whether the signal used > to transmit it is analog or digital (and it can indeed > be either, without regard to the message). You specifically mentioned "wire cables and fiber optic cables", so lets talk about those and ignore other possible transmission media. In both of those (as they are actually used in the real world), communication is accomplished by the propagation along them of electromagnetic fields; never anything else. Doesn't matter one whit whether you turn the field on and off, or vary the amplitude or any other characteristic of it continuously, as a means of sending a message from one end to the other, those fields can take on *any value* from the maximum level injected into the cable by the transmitter down to far below the ambient noise level, depending (for example) on the length of cable being used. IOW, those signals are, without exception, *analog*. Isaac |
|
#484
| |||
| |||
| In article <87sl63i4mb.fld@apaflo.com>, floyd@apaflo.com (Floyd L. Davidson) wrote: > "Bob Myers" <nospamplease@address.invalid> wrote: > >"isw" <isw@witzend.com> wrote in message > >news:isw-00A66F.10310528082007@newsgroups.comcast.net... > >> In article <87mywcjdq7.fld@apaflo.com>, > >> floyd@apaflo.com (Floyd L. Davidson) wrote: > >> > >>> Most physical channels are inherently analog! Wire > >>> cables and fiber optic cables are two examples. Digital > >>> signals are commonly sent via either of them. > >> > >> I'll probably regret jumping in here, but: > >> > >> The *message* may be digital, but the *signals* are most definitely > >> analog. > > > >The SIGNALS are electrical or optical. > > Really? Nothing could be acoustical? Are you deaf? > > Regardless, that does not address the incorrectness of > stating that all signals are analog. Morse code is not > analog. The carrier or tone that is keyed on and off to send the code starts out at a certain strength at the transmitter and grows weaker in a continuous fashion as the receiver moves further and further away, until at some point it becomes impossible to understand the *message* it is carrying. That is, the signal is analog. How can it be digital if it can take on *any* value? Isaac |
|
#485
| |||
| |||
| "Mr.T" <MrT@home> wrote: >"Floyd L. Davidson" <floyd@apaflo.com> wrote in message >news:87r6lojir0.fld@apaflo.com... >> >> Yes, you do have an infinite number of *voltages* >> >> between 3 and 18, >> > >> >Only in theory, in practice nothing is infinite in this universe. >> >Noise will set the resolution limit. >> >> The noise itself has an infinite number of possible >> values, > >OK, prove it. Eh? You seem to have misunderstood what was said. It has *nothing* to do with resolution. It has to do with the fact that no matter what level the noise is, it could be either a little bit more or a little bit less. That means whatever value you think you have resolved, could in fact actually have had two other possible values. Which of course means that the number of voltages between 3 and 18 is indeed infinite, with or without noise. Your ability to resolve those values is an entirely different topic. >> and therefore even if the signal itself is >> supposed to be just 1 value, add the noise and there are >> an infinite number of values. > >Only for those who failed mathematics at high school. Add a random number with an infinite range of possible values to *anything*, and you have a result with an infinite range of possible values. Pretty simple math. I'm sorry to hear that you didn't do well with math in highschool. -- Floyd L. Davidson <http://www.apaflo.com/floyd_davidson> Ukpeagvik (Barrow, Alaska) floyd@apaflo.com |
|
#486
| |||
| |||
| isw <isw@witzend.com> wrote: > floyd@apaflo.com (Floyd L. Davidson) wrote: >In both of those (as they are actually used in the real world), >communication is accomplished by the propagation along them of >electromagnetic fields; never anything else. > >Doesn't matter one whit whether you turn the field on and off, or vary >the amplitude or any other characteristic of it continuously, as a means >of sending a message from one end to the other, those fields can take on >*any value* from the maximum level injected into the cable by the Yes, the electrical fields can take any value. It is inherently an analog medium. But that has no relationship to the signal which is used to send a message. The *signal* does or does not have the ability to take on various values. If the signal uses discrete symbols, it is a digital signal. If the symbols have a continuous range of values, it is an analog signal. This is not an insignificant distinction. It precisely the reason that at Bell Labs Claude Shannon studied the theory of how the two differ. As a result of his Theory of Information the telecommunications industry began to develop the technology required to implement digital system to replace the existing analog systems. They did that based on what Shannon had shown to be theoretically the most effective for telecommunications. Digital systems typically trade SNR (which can be very low) for bandwidth (which will be very high) compared to using analog signaling. The inherent noise immunity of a digital system is great, and because the analog noise in the medium is *not* directly proportional to the signal value, a digital signal can be transmitted with zero errors (due to noise) if the SNR on the analog medium is above a minimal level. It happens that that SNR is so low that a system using analog signals would be unusable at the same SNR. (Fiber optic cables are an example, where they are virtually useless with analog signaling for the typical long circuit lengths that are provided when digital signaling is used.) The actual minimum SNR depends on the type of digital encoding used. But some typical values for various communications purposes are interesting to look at. A dialup telephone connection is supposed to have at least a 24 dB SNR. That is relatively useful for voice communications, but a typical dialup modem won't work very well unless the SNR of the connection is above 30 dB above random noise (because it has been converted to a bandwidth limited analog signal). On the other hand a binary polar signal (such as the RS-232C digital interface to that dialup modem) will have an error rate of less than 1 in 10^5 with an SNR of only 9.5 dB. But that isn't even the most significant benefit! Noise is additive on an analog system, but not on a digital system, which is specifically the difference between digital and analog that has revolutionized all telecommunications in the years since Shannon showed that digital was superior. What that means is if we use 5 analog channels tandem linked to get our message from one location to another, the end to end noise must be added to determine the SNR, and that total SNR must meet the above criteria for a higher SNR than is needed by a digital system. But if 5 digital channels are tandem linked, only the errors are additive and not the noise. That is, with analog both the noise and the errors in the first link are sent to all succeeding links, and that noise causes errors in each link on analog system. On a digital system only the errors are inputted to the succeeding links but not the noise, so noise in the first link does not cause errors in the succeeding links as it does with an analog system. >transmitter down to far below the ambient noise level, depending (for >example) on the length of cable being used. IOW, those signals are, >without exception, *analog*. No, those signals are digital if the symbols they use are discrete. The fact that the voltage, for example can range from 0 to 1 volt has no significance in terms of the signal *if* that signal uses exactly two symbols, one of which is represented by any voltage less than 0.4 volts and one of which is represented by any voltage greater than 0.6 volts. That describes a digital signal (which indeed is being sent through an inherently analog channel). encoder medium decoder +------+ +------+ | | | | input >----+ +---------------+ +----> output | | | | +------+ +------+ | | |<---Analog --->| | Channel | | | |<--------------- Digital -------------->| | Channel | Typical examples of the above are where the input to the "encoder" is a DS1 and the "medium" is a twisted pair cable, or where that input is an OC3 and the "medium" is a fiber optic cable, or where the encoder is a satellite modem and the medium is a "bent-pipe" geosynchronous satellite. -- Floyd L. Davidson <http://www.apaflo.com/floyd_davidson> Ukpeagvik (Barrow, Alaska) floyd@apaflo.com |
|
#487
| |||
| |||
| isw <isw@witzend.com> wrote: > floyd@apaflo.com (Floyd L. Davidson) wrote: >> > >> >The SIGNALS are electrical or optical. >> >> Really? Nothing could be acoustical? Are you deaf? I should have put a smiley on that, sorry for missing it. >> Regardless, that does not address the incorrectness of >> stating that all signals are analog. Morse code is not >> analog. > >The carrier or tone that is keyed on and off to send the code starts out Morse code does not necesarily have either a carrier or a tone involved, but we can ignore that for this discussion without changing the validity of our conclusions. >at a certain strength at the transmitter and grows weaker in a >continuous fashion as the receiver moves further and further away, until >at some point it becomes impossible to understand the *message* it is >carrying. Well, lets take exactly that as an example, because it is a good one. We could use a tone as the carrier if you like, and send it down a regular twisted pair cable. I'm going to describe this for Morse Code signaling, but I'd like to point out that virtually any FSK modem does exactly the same thing with exactly the dynamic range I'm describing here. Instead of on/off though, it uses two tones. Everything else is the same, except the modem is many times faster than a human can decode Morse Code. If we put it on the cable at 0 dBm, we'll likely have an SNR of roughly 50 dB or so, plus or minus a few. The message is sent using on/off keying of a tone, so at the cable head we have a 50 dB range which is used to determine on vs. off. If we head down the road several miles and get to a point where the signal level has dropped 10 dB (about the maximum that can be used by a POTS line), we now have a 40 dB SNR range to deal with. We could go twice that distance again (losing 10 dB of signal each time) and get to a point where our signal is -30 dB and we have only a 20 dB SNR. At 20 dB SNR there is no reason at all that you won't get perfect copy, with no errors. Clearly the *signal* has not changed, even though it has dropped 30 dB in power. That is because the symbols used are discrete. From perhaps -40 dBm to 0 dBm there is *no* *change* *in* *the* *value* *of* *the* *symbols*! >That is, the signal is analog. How can it be digital if it can take on >*any* value? Obviously it does *not* take on any value. The value for Morse code is either on or off. There is no "on at -22.4 dB" value, just on. -- Floyd L. Davidson <http://www.apaflo.com/floyd_davidson> Ukpeagvik (Barrow, Alaska) floyd@apaflo.com |
![]() |
| Thread Tools | |
| Display Modes | |
In an effort to better serve ads to our visitors, cookies are used on objectmix.com. For more information, check out our Privacy Policy.